Random Number Generator
Published: Jun 19, 2015
Surprisingly this is something that I come across quite often and it’s not the easiest thing to achieve in SQL Server in certain circumstances… a solid piece of code which generates a random number.

We all know that the rand() function exists within SQL Server and therefore this is what most people choose as their solution. However, this can suddenly become less than useful when dealing with sets rather than singular values.

So let’s have a look at the rand() function:

select rand() as random
go 5

As you can see, running this 5 times gives us 5 different, and random numbers. All good. From this we can easily get a random number generated between, for example 1 and 100:

select floor(rand()*100)+1 as random
go 5

However, what happens when we use rand() in a query?

select floor(rand()*100)+1 as random, name
from sys.objects

Now we’ve got a massive problem. But why?

Well, what happens is that rand() is evaluated just the once per batch and therefore this means that you can obtain a random number, but only the once, therefore in a set based output it becomes rather useless.

Hence why I’m always asked how it’s possible to actually produce a random number in a set based resultset.

Well, there is a way… use newID() instead.

This is evaluated for each row and not just each batch. However, there’s a small problem… it’s a GUID:

select newID() as random, name
from sys.objects

The advantage is that being a GUID it does mean that the necessary randomness of the output can be almost guaranteed, but we do need it in a numeric format.

So, in order to get a random number out of this we can do the following:

First convert the GUID into a 1 byte binary. This makes the GUID just 1 byte, the same as a tinyint. Therefore this effectively turns the GUID into a number between 0 and 255…

select convert(int, convert(varbinary(1), newID())) as random, name
from sys.objects

Once done we can now convert this into a decimal which we then use to generate our random number between 1 and 100 (note that this time we use 99 as our feed value instead of 100):

select floor((convert(int, convert(varbinary(1), newID()))/255.0*99)+1) as random, name
from sys.objects

Therefore, for any random set of values between 1 and X you would use the following:

declare @topLimit int = X

select floor((convert(int, convert(varbinary(1), newID()))/255.0*@topLimit)+1) as random, name
from sys.objects

And it’s as simple as that.
Leave a Comment
Your email address will not be published. All fields are mandatory.
NB: Comments will only appear once they have been moderated.

Your SQL Trainer
Kevin Urquhart

I am a SQL Server DBA, Architect, Developer, and Trainer for SQL Training. This is my blog in which I’m simply trying to share my SQL knowledge and experiences with the world.

Kevin Urquhart
SQL Server Consultant, London



Copyright © 2018 London SQL Server Training Courses @ SQL Training | Website Design From Scott Heron